看完上面的评审后，也许有些读者已经急切地想找一些代码来试验一下看能否通过上面的内容来提高自己的检视能力。下面就讲几个代码检视的实例，请读者在看这些实例时先不要看后面的分析，自己先拿张纸边看代码边把自己能够发现的问题记录下来，然后再和后面的分析进行比较。如果能够发现后现分析中没有提及的问题，说明已经将评审检视基本功学得非常好了。日志文件函数的代码如下：/**写日志函数，实现将日志信息写入日志文件中的功能@paramchar*pszLogFile-日志文件名 @pa

VC# 窗体 150个实例

一款帮助大家理解爬虫的Demo，通过这款Demo，我想各位肯定会更理解一点

时间函数举例程序分析 2.程序源代码： #include "stdio.h" #include "time.h" void main() { time_t lt; /*define a longint time varible*/ lt=time(NULL);/*system time and date*/ printf(ctime(<)); /*english format output*/ printf(asctime(localtime(<)));/*tranfer to tm*/ printf(asctime(gmtime(<))); /*tranfer to Greenwich time*/ } 【程序92】 题目：时间函数举例2 1.程序分析： 2.程序源代码： /*calculate time*/ #include "time.h" #include "stdio.h" main() { time_t start,end; int i; start=time(NULL); for(i=0;i<3000;i++) { printf("\1\1\1\1\1\1\1\1\1\1\n"); } end=time(NULL); printf("\1: The different is %6.3f\n",difftime(end,start)); } 【程序93】 题目：时间函数举例3 1.程序分析： 2.程序源代码： /*calculate time*/ #include "time.h" #include "stdio.h" main() { clock_t start,end; int i; double var; start=clock(); for(i=0;i<10000;i++) { printf("\1\1\1\1\1\1\1\1\1\1\n"); } end=clock(); printf("\1: The different is %6.3f\n",(double)(end-start)); } 【程序94】 题目：时间函数举例4,一个猜数游戏，判断一个人反应快慢。（版主初学时编的） 1.程序分析： 2.程序源代码： #include "time.h" #include "stdlib.h" #include "stdio.h" main() { char c; clock_t start,end; time_t a,b; double var; int i,guess; srand(time(NULL)); printf("do you want to play it.('y' or 'n') \n"); loop: while((c=getchar())=='y') { i=rand()%100; printf("\nplease input number you guess:\n"); start=clock(); a=time(NULL); scanf("%d",&guess); while(guess!=i) { if(guess>i) { printf("please input a little smaller.\n"); scanf("%d",&guess); } else { printf("please input a little bigger.\n"); scanf("%d",&guess); } } end=clock(); b=time(NULL); printf("\1: It took you %6.3f seconds\n",var=(double)(end-start)/18.2); printf("\1: it took you %6.3f seconds\n\n",difftime(b,a)); if(var<15) printf("\1\1 You are very clever! \1\1\n\n"); else if(var<25) printf("\1\1 you are normal! \1\1\n\n"); else printf("\1\1 you are stupid! \1\1\n\n"); printf("\1\1 Congradulations \1\1\n\n"); printf("The number you guess is %d",i); } printf("\ndo you want to try it again?(\"yy\".or.\"n\")\n"); if((c=getch())=='y') goto loop; } 【程序95】 题目：家庭财务管理小程序 1.程序分析： 2.程序源代码： /*money management system*/ #include "stdio.h" #include "dos.h" main() { FILE *fp; struct date d; float sum,chm=0.0; int len,i,j=0; int c; char ch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8]; pp: clrscr(); sum=0.0; gotoxy(1,1);printf("|----------------------------------------------------|"); gotoxy(1,2);printf("| money management system(C1.0) 2000.03 |"); gotoxy(1,3);printf("|----------------------------------------------------|"); gotoxy(1,4);printf("| -- money records -- | -- today cost list -- |"); gotoxy(1,5);printf("| ------------------------ |-----------------------------|"); gotoxy(1,6);printf("| date: -------------- | |"); gotoxy(1,7);printf("| | | | |"); gotoxy(1,8);printf("| -------------- | |"); gotoxy(1,9);printf("| thgs: ------------------ | |"); gotoxy(1,10);printf("| | | | |"); gotoxy(1,11);printf("| ------------------ | |"); gotoxy(1,12);printf("| cost: ---------- | |"); gotoxy(1,13);printf("| | | | |"); gotoxy(1,14);printf("| ---------- | |"); gotoxy(1,15);printf("| | |"); gotoxy(1,16);printf("| | |"); gotoxy(1,17);printf("| | |"); gotoxy(1,18);printf("| | |"); gotoxy(1,19);printf("| | |"); gotoxy(1,20);printf("| | |"); gotoxy(1,21);printf("| | |"); gotoxy(1,22);printf("| | |"); gotoxy(1,23);printf("|--------------------------------------------------|"); i=0; getdate(&d); sprintf(chtime,"%4d.%02d.%02d",d.da_year,d.da_mon,d.da_day); for(;;) { gotoxy(3,24);printf(" Tab __browse cost list Esc __quit"); gotoxy(13,10);printf(" "); gotoxy(13,13);printf(" "); gotoxy(13,7);printf("%s",chtime); j=18; ch[0 ]=getch(); if(ch[0]==27) break; strcpy (chshop,""); strcpy(chmoney,""); if(ch[0]==9) { mm:i=0; fp=fopen("home.dat","r+"); gotoxy(3,24);printf(" "); gotoxy(6,4);printf(" list records "); gotoxy(1,5);printf("|-------------------------------------|"); gotoxy(41,4);printf(" "); gotoxy(41,5);printf(" |"); while(fscanf(fp,"%10s%14s%f\n",chtime,chshop,&chm)!=EOF) { if(i==36) { getch(); i=0; } if ((i%36)<17) { gotoxy(4,6+i); printf(" "); gotoxy(4,6+i); } else if((i%36)>16) { gotoxy(41,4+i-17); printf(" "); gotoxy(42,4+i-17); } i++; sum=sum+chm; printf("%10s %-14s %6.1f\n",chtime,chshop,chm);} gotoxy(1,23);printf("|----------------------------------------------|"); gotoxy(1,24);printf("| |"); gotoxy(1,25);printf("|----------------------------------------------|"); gotoxy(10,24);printf("total is %8.1f$",sum); fclose(fp); gotoxy(49,24);printf("press any key to.....");getch();goto pp; } else { while(ch[0]!='\r') { if(j<10) { strncat(chtime,ch,1); j++; } if(ch[0]==8) { len=strlen(chtime)-1; if(j>15) { len=len+1; j=11; } strcpy(ch1,""); j=j-2; strncat(ch1,chtime,len); strcpy(chtime,""); strncat(chtime,ch1,len-1); gotoxy(13,7);printf(" "); } gotoxy(13,7);printf("%s",chtime);ch[0]=getch(); if(ch[0]==9) goto mm; if(ch[0]==27) exit(1); } gotoxy(3,24);printf(" "); gotoxy(13,10); j=0; ch[0]=getch(); while(ch[0]!='\r') { if (j<14) { strncat(chshop,ch,1); j++; } if(ch[0]==8) { len=strlen(chshop)-1; strcpy(ch1,""); j=j-2; strncat(ch1,chshop,len); strcpy(chshop,""); strncat(chshop,ch1,len-1); gotoxy(13,10);printf(" "); } gotoxy(13,10);printf("%s",chshop);ch[0]=getch();} gotoxy(13,13); j=0; ch[0]=getch(); while(ch[0]!='\r') { if (j<6) { strncat(chmoney,ch,1); j++; } if(ch[0]==8) { len=strlen(chmoney)-1; strcpy(ch1,""); j=j-2; strncat(ch1,chmoney,len); strcpy(chmoney,""); strncat(chmoney,ch1,len-1); gotoxy(13,13);printf(" "); } gotoxy(13,13);printf("%s",chmoney);ch[0]=getch(); } if((strlen(chshop)==0)||(strlen(chmoney)==0)) continue; if((fp=fopen("home.dat","a+"))!=NULL); fprintf(fp,"%10s%14s%6s",chtime,chshop,chmoney); fputc('\n',fp); fclose(fp); i++; gotoxy(41,5+i); printf("%10s %-14s %-6s",chtime,chshop,chmoney); } } } 【程序96】 题目：计算字符串中子串出现的次数 1.程序分析： 2.程序源代码： #include "string.h" #include "stdio.h" main() { char str1[20],str2[20],*p1,*p2; int sum=0; printf("please input two strings\n"); scanf("%s%s",str1,str2); p1=str1;p2=str2; while(*p1!='\0') { if(*p1==*p2) { while(*p1==*p2&&*p2!='\0') { p1++; p2++; } } else p1++ ; if(*p2=='\0') sum++; p2=str2; } printf("%d",sum); getch(); } 【程序97】 题目：从键盘输入一些字符，逐个把它们送到磁盘上去，直到输入一个#为止。 1.程序分析： 2.程序源代码： #include "stdio.h" main() { FILE *fp; char ch,filename[10]; scanf("%s",filename); if((fp=fopen(filename,"w"))==NULL) { printf("cannot open file\n"); exit(0); } ch=getchar(); ch=getchar(); while(ch!='#') { fputc(ch,fp);putchar(ch); ch=getchar(); } fclose(fp); } 【程序98】 题目：从键盘输入一个字符串，将小写字母全部转换成大写字母，然后输出到一个磁盘文件"test"中保存。输入的字符串以！结束。 1.程序分析： 2.程序源代码： #include "stdio.h" main() { FILE *fp; char str[100],filename[10]; int i=0; if((fp=fopen("test","w"))==NULL) { printf("cannot open the file\n"); exit(0); } printf("please input a string:\n"); gets(str); while(str[i]!='!') { if(str[i]>='a'&&str[i]<='z') str[i]=str[i]-32; fputc(str[i],fp); i++; } fclose(fp); fp=fopen("test","r"); fgets(str,strlen(str)+1,fp); printf("%s\n",str); fclose(fp); } 【程序99】 题目：有两个磁盘文件A和B,各存放一行字母，要求把这两个文件中的信息合并（按字母顺序排列）， 输出到一个新文件C中。 1.程序分析： 2.程序源代码： #include "stdio.h" main() { FILE *fp; int i,j,n,ni; char c[160],t,ch; if((fp=fopen("A","r"))==NULL) { printf("file A cannot be opened\n"); exit(0); } printf("\n A contents are :\n"); for(i=0;(ch=fgetc(fp))!=EOF;i++) { c[i]=ch; putchar(c[i]); } fclose(fp); ni=i; if((fp=fopen("B","r"))==NULL) { printf("file B cannot be opened\n"); exit(0); } printf("\n B contents are :\n"); for(i=0;(ch=fgetc(fp))!=EOF;i++) { c[i]=ch; putchar(c[i]); } fclose(fp); n=i; for(i=0;ic[j]) { t=c[i];c[i]=c[j];c[j]=t; } printf("\n C file is:\n"); fp=fopen("C","w"); for(i=0;i

2022-06-11 16:20:47 10KB C语言程序设计实例（200行）

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